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jquery和servlet如何传递JSON数组

例 3.7（AjaxJsonArray.jsp）
马克- to-win：马克 java社区：防盗版实名手机尾号： 73203。
<html>
<head>

<script src="jquery.js"></script>
<script type="text/javascript">
    function getP(id) {
        $.getJSON("jqueryservlet37", {
            id : id
        }, function(arr) {
            for ( var i = 0; i < arr.length; i++) {
                var obj = arr[i];
                for ( var pro in obj) {
                     document.getElementById(pro).innerHTML = obj[pro];
                }
            }

            /* document.getElementById(pro).innerHTML = obj[pro];和下一句一样。
             $("#"+pro).html(obj[pro]);
             */
        })
    }
</script>
</head>

<body>
    <table width="340" border="1">
        <tr>
            <td id="1" onclick="getP('1')">点这1</td>
            <td id="2" onclick="getP('2')">点这2</td>
        </tr>
    </table>

    <table width="340" border="1">
        <tr>
            <td width="170">参数项</td>
            <td width="170">参数值</td>
        </tr>
        <tr>
            <td>型号</td>
            <td id="type"> </td>
        </tr>
        <tr>
            <td>价格</td>
            <td id="price"> </td>
        </tr>
        <tr>
            <td>型号1</td>
            <td id="type1"> </td>
        </tr>
        <tr>
            <td>价格1</td>
            <td id="price1"> </td>
        </tr>
    </table>
</body>
</html>

package helloWorld;

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.json.simple.JSONArray;
import org.json.simple.JSONObject;

public class jqueryservlet37 extends HttpServlet {
    public void doGet(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {

        response.setContentType("text/html;charset=UTF-8");
        PrintWriter out = response.getWriter();
        String id = request.getParameter("id");
        JSONArray arr = new JSONArray();
        JSONObject o = new JSONObject();
        o.put("type","adslqixy"+id);
        o.put("price","333qixy"+id);
        arr.add(o);
        o = new JSONObject ();
        o.put("type1","adslqixy"+id+id);
        o.put("price1","666qixy"+id+id);
        arr.add(o);

        System.out.println("arr.toString() is" + arr.toString());
        out.print(arr.toString());
    }

    public void doPost(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        this.doGet(request, response);

    }

}

js jquery